Solve following:

$\displaystyle Ix-4I+2x<7$

Those I:s mean absolute value...

Well I did this..

$\displaystyle (-7)<x-4+2x<7$ $\displaystyle /+4$

$\displaystyle (-3)<3x<11$ $\displaystyle / /3$

$\displaystyle (-1)<x<11/3$ but that is apparently very wrong...correct answer is x<3

Any idea where I wen´t wrong?