Hello,
I have a question regarding a problem that my prof gave me:
x=y
then
x² = xy
x²- y²= xy- y²
(x-y) (x+y) = (x-y) y
x+y= y
y+y=y
2y=y
which would mean that 2=1
Can someone explain me where the problem is?
Thanks in adavance!
Hello,
I have a question regarding a problem that my prof gave me:
x=y
then
x² = xy
x²- y²= xy- y²
(x-y) (x+y) = (x-y) y
x+y= y
y+y=y
2y=y
which would mean that 2=1
Can someone explain me where the problem is?
Thanks in adavance!
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