I have forgotten the easiest way to do this. I need to solve for z: (3) / (z - 3) + (5) / (z - 1) = (8) / (z - 2) Thanks as always for your help!
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Originally Posted by jay1 I have forgotten the easiest way to do this. I need to solve for z: (3) / (z - 3) + (5) / (z - 1) = (8) / (z - 2) Thanks as always for your help! Write everything with a common denominator.
Originally Posted by jay1 I have forgotten the easiest way to do this. I need to solve for z: (3) / (z - 3) + (5) / (z - 1) = (8) / (z - 2) Thanks as always for your help! Multiply both sides of the equation by the LCD: In this case, it is $\displaystyle (z-1)(z-2)(z-3)$
Originally Posted by vonnemo19 multiply both sides of the equation by the lcd: In this case, it is $\displaystyle (z-1)(z-2)(z-3)$ z = 6?
Originally Posted by jay1 z = 6? Correct.
Originally Posted by jay1 z = 6? Well, Lets see what happens when we plug it back in $\displaystyle \frac{3}{6-3}+\frac5{6-1}=\frac8{6-2}$ Is $\displaystyle 1+1\neq2$?
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