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Math Help - simplifying complex fractions

  1. #1
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    simplifying complex fractions

    Please assist in simplifying the following complex fraction (I cannot format correctly, but there is a bold line in between the following two expressions) b^2 + 5b + 6/ 3bc (bold line, and underneath b^2 - 9/6bc I'm coming up with -1, but this doesn't seem correct?
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  2. #2
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    Quote Originally Posted by jay1 View Post
    Please assist in simplifying the following complex fraction (I cannot format correctly, but there is a bold line in between the following two expressions) b^2 + 5b + 6/ 3bc (bold line, and underneath b^2 - 9/6bc I'm coming up with -1, but this doesn't seem correct?
    remember how to divide fractions?

    \frac{b^2+5b+6}{3bc} \cdot \frac{6bc}{b^2-9}

    \frac{(b+2)(b+3)}{3bc} \cdot \frac{6bc}{(b+3)(b-3)}

    finish
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  3. #3
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    Quote Originally Posted by skeeter View Post
    remember how to divide fractions?

    \frac{b^2+5b+6}{3bc} \cdot \frac{6bc}{b^2-9}

    \frac{(b+2)(b+3)}{3bc} \cdot \frac{6bc}{(b+3)(b-3)}

    finish
    Thanks..I think I have it: 2(b+2)/(b - 3) ?
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