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Math Help - basic index

  1. #1
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    basic index

    can any one help / fill in the blank for the following problem. i already derive but still stuck.

    tq for help
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  2. #2
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    Quote Originally Posted by nikk View Post
    can any one help / fill in the blank for the following problem. i already derive but still stuck.

    tq for help
    3\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)

    that's as far as you can go.
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  3. #3
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    Quote Originally Posted by skeeter View Post
    3\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)

    that's as far as you can go.
    how you get the answer???

    3\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)

    or
    did u mean my last answer before question mark is accepted??
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  4. #4
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    I meant what you arrived at at your last step ...

    \frac{3}{4}\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)


    forgot the denominator of 4 under the leading 3


    4^{\frac{4}{3}} + 3^{\frac{4}{3}} cannot be simplified further
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  5. #5
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    Quote Originally Posted by skeeter View Post
    I meant what you arrived at at your last step ...

    \frac{3}{4}\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)


    forgot the denominator of 4 under the leading 3


    4^{\frac{4}{3}} + 3^{\frac{4}{3}} cannot be simplified further
    i confuse for your first post because there is forgot the denominator of 4 under the leading 3

    now i understand
    tq very much sir
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