# basic index

• Jan 24th 2010, 03:35 PM
nikk
basic index
can any one help / fill in the blank for the following problem. i already derive but still stuck.

tq for help
• Jan 24th 2010, 03:49 PM
skeeter
Quote:

Originally Posted by nikk
can any one help / fill in the blank for the following problem. i already derive but still stuck.

tq for help

$\displaystyle 3\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)$

that's as far as you can go.
• Jan 24th 2010, 04:09 PM
nikk
Quote:

Originally Posted by skeeter
$\displaystyle 3\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)$

that's as far as you can go.

$\displaystyle 3\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)$

or
did u mean my last answer before question mark is accepted??
• Jan 24th 2010, 04:25 PM
skeeter
I meant what you arrived at at your last step ...

$\displaystyle \frac{3}{4}\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)$

forgot the denominator of 4 under the leading 3

$\displaystyle 4^{\frac{4}{3}} + 3^{\frac{4}{3}}$ cannot be simplified further
• Jan 24th 2010, 04:31 PM
nikk
Quote:

Originally Posted by skeeter
I meant what you arrived at at your last step ...

$\displaystyle \frac{3}{4}\left(4^{\frac{4}{3}} + 3^{\frac{4}{3}}\right)$

forgot the denominator of 4 under the leading 3

$\displaystyle 4^{\frac{4}{3}} + 3^{\frac{4}{3}}$ cannot be simplified further

i confuse for your first post because there is forgot the denominator of 4 under the leading 3

now i understand
tq very much sir