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Math Help - Help solving for z

  1. #1
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    Help solving for z

    (3/z - 3) + (5/z - 1) = (8/z - 2) Is z negative or positive in this case?
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by jay1 View Post
    (3/z - 3) + (5/z - 1) = (8/z - 2) Is z negative or positive in this case?
    solve it and see.

    first step here. multiply both sides by z. see what you can do from there.
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  3. #3
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    Quote Originally Posted by jay1 View Post
    (3/z - 3) + (5/z - 1) = (8/z - 2) Is z negative or positive in this case?
    is the equation ...

    \left(\frac{3}{z} - 3\right) + \left(\frac{5}{z} - 1\right) = \left(\frac{8}{z} - 2\right)

    or

    \frac{3}{z-3} + \frac{5}{z-1} = \frac{8}{z-2}

    ???
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    Quote Originally Posted by skeeter View Post
    is the equation ...

    \left(\frac{3}{z} - 3\right) + \left(\frac{5}{z} - 1\right) = \left(\frac{8}{z} - 2\right)

    or

    \frac{3}{z-3} + \frac{5}{z-1} = \frac{8}{z-2}

    ???
    Skeeter, the equation is the latter. Thanks!
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  5. #5
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    \frac{3}{z-3} + \frac{5}{z-1} = \frac{8}{z-2}

    you need a common denominator
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by jay1 View Post
    Skeeter, the equation is the latter. Thanks!
    well, that makes a world of difference. next time, use parentheses! or better yet, learn LaTeX (see my signature).

    to start you off: multiply both sides of the equation by the LCD. in this case, that's (z - 1)(z - 2)(z - 3)
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    Quote Originally Posted by Jhevon View Post
    well, that makes a world of difference. next time, use parentheses! or better yet, learn LaTeX (see my signature).

    to start you off: multiply both sides of the equation by the LCD. in this case, that's (z - 1)(z - 2)(z - 3)
    Does z = -4 ???
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  8. #8
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by jay1 View Post
    Does z = -4 ???
    no.

    (you can check this by plugging that value for z into the original equation. you will see that the equation does not make sense with that z-value)

    what was your next step after doing what i said?
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