Results 1 to 4 of 4

Math Help - Help dividing expression

  1. #1
    Member
    Joined
    Dec 2009
    Posts
    122

    Help dividing expression

    27z + 23z^2 + 6z^3 divided by 2z + 3. I have come up with 3z^2 + 7z +3 and a remainder of -9?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by jay1 View Post
    27z + 23z^2 + 6z^3 divided by 2z + 3. I have come up with 3z^2 + 7z +3 and a remainder of -9?
    correct
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    Correct

    Next time, if you want to check your answer, just do the operation back :

    does (2z+3)(3z^2+7z+3)-9 equal 6z^3+23z^2+27z ?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    12,130
    Thanks
    1011
    Quote Originally Posted by jay1 View Post
    27z + 23z^2 + 6z^3 divided by 2z + 3. I have come up with 3z^2 + 7z +3 and a remainder of -9?
    that's what I got.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 20
    Last Post: January 15th 2012, 10:30 AM
  2. Replies: 6
    Last Post: October 6th 2011, 02:48 PM
  3. Replies: 5
    Last Post: June 1st 2011, 08:27 PM
  4. dividing
    Posted in the Pre-Calculus Forum
    Replies: 6
    Last Post: July 17th 2009, 11:23 AM
  5. Dividing
    Posted in the Advanced Math Topics Forum
    Replies: 6
    Last Post: January 3rd 2008, 01:39 PM

Search Tags


/mathhelpforum @mathhelpforum