27z + 23z^2 + 6z^3 divided by 2z + 3. I have come up with 3z^2 + 7z +3 and a remainder of -9?

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- Jan 24th 2010, 03:04 PMjay1Help dividing expression
27z + 23z^2 + 6z^3 divided by 2z + 3. I have come up with 3z^2 + 7z +3 and a remainder of -9?

- Jan 24th 2010, 03:18 PMJhevon
- Jan 24th 2010, 03:18 PMMoo
Correct (Yes)

Next time, if you want to check your answer, just do the operation back :

does $\displaystyle (2z+3)(3z^2+7z+3)-9$ equal $\displaystyle 6z^3+23z^2+27z$ ? - Jan 24th 2010, 03:19 PMskeeter