# Help dividing expression

• January 24th 2010, 03:04 PM
jay1
Help dividing expression
27z + 23z^2 + 6z^3 divided by 2z + 3. I have come up with 3z^2 + 7z +3 and a remainder of -9?
• January 24th 2010, 03:18 PM
Jhevon
Quote:

Originally Posted by jay1
27z + 23z^2 + 6z^3 divided by 2z + 3. I have come up with 3z^2 + 7z +3 and a remainder of -9?

correct
• January 24th 2010, 03:18 PM
Moo
Correct (Yes)

Next time, if you want to check your answer, just do the operation back :

does $(2z+3)(3z^2+7z+3)-9$ equal $6z^3+23z^2+27z$ ?
• January 24th 2010, 03:19 PM
skeeter
Quote:

Originally Posted by jay1
27z + 23z^2 + 6z^3 divided by 2z + 3. I have come up with 3z^2 + 7z +3 and a remainder of -9?

that's what I got.