Solve for x: $\displaystyle Ix-9I$+$\displaystyle Ix-5I $when $\displaystyle Ix-7I$$\displaystyle < 1$ Those I-I s represent abs: from the second inequality I got: $\displaystyle 6<x<8$ But I donīt get that adding part....
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Originally Posted by Henryt999 Solve for x: $\displaystyle Ix-9I$+$\displaystyle Ix-5I $when $\displaystyle Ix-7I$$\displaystyle < 1$ Those I-I s represent abs: from the second inequality I got: $\displaystyle 6<x<8$ But I donīt get that adding part.... hi solve for x ?? |x-7|<1 , -1<x-7<1 therefore , 6<x<8 , x=7 assuming that its an integer . |7-9|+|7-5|=4
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