I can factorize problems like this:
3x^2 + 5x
3x^2: (1) (3) (x) (x)
5x: (1) (5) (x)
Using 1 and x to drop outside and use the leftovers:
x(3x + 5) *final*
But I'm being stumped by this kind of problem:
(x + 2)^2 - 5(x + 2) ?
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Originally Posted by robbz But I'm being stumped by this kind of problem:
(x + 2)^2 - 5(x + 2) ? First expand both sets of brackets:
Collect like terms:
Then factorise like you would a normal quadratic equation (I am assuming that you have come across these before, if not please say).
Hope this helps.
Ok, so when you left off at x^2 - x - 6.
How do I factorize that? It's longer than the binomials I've been doing.
Think about it like this:
So, we see that is common in both terms, so we factor the whole thing out:
Then you can simplify the right half.
Robbz, drumist's response is the one to go with!
Thanks for the help everyone.
I understand it now.
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