I can factorize problems like this: 3x^2 + 5x 3x^2: (1) (3) (x) (x) 5x: (1) (5) (x) Using 1 and x to drop outside and use the leftovers: x(3x + 5) *final* But I'm being stumped by this kind of problem: (x + 2)^2 - 5(x + 2) ?
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Originally Posted by robbz But I'm being stumped by this kind of problem: (x + 2)^2 - 5(x + 2) ? First expand both sets of brackets: Collect like terms: Then factorise like you would a normal quadratic equation (I am assuming that you have come across these before, if not please say). Hope this helps.
Ok, so when you left off at x^2 - x - 6. How do I factorize that? It's longer than the binomials I've been doing.
Think about it like this: So, we see that is common in both terms, so we factor the whole thing out: Then you can simplify the right half.
Robbz, drumist's response is the one to go with!
Thanks for the help everyone. I understand it now.
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