Thread: Trigonometric Functions

I am totally lost and have no idea how to do any of these

Originally Posted by Tarwamin

I am totally lost and have no idea how to do any of these

And by these you mean....what, exactly?

EDIT: I see the image now.


Hey, have you tried anything?

yes..but my teacher said it was all wrong

Originally Posted by Tarwamin

yes..but my teacher said it was all wrong

And he/she wouldn't help you? Show me a little of what you tried for say-I don't know- #1 perhaps.

i still have to do #1..i'll show u #2...

2sinx=sin^2+cos^2x
2sinx=1
sinx= 1/2
x= sin (inverse) (1/2)
x= 180/6
x=30

0<30<2(180)

Originally Posted by Tarwamin

i still have to do #1..i'll show u #2...

2sinx=sin^2+cos^2x
2sinx=1
sinx= 1/2
x= sin (inverse) (1/2)
x= 180/6
x=30

0<30<2(180)

Hey, that's great work, but I really not making the connection to "#2" here. You were asked to explain why the asymptotes of the graph of are found where they are.

oops..wrong post :$