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Math Help - simplify..need help

  1. #1
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    simplify..need help

    Hello
    Can someone tell me how to simplify this further?

    (-18x^4)+(24^3)/(6x^3)^2

    (6x^3)^2 is the common denom!

    Please help
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  2. #2
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    Quote Originally Posted by wolfhound View Post
    Hello
    Can someone tell me how to simplify this further?

    (-18x^4)+(24^3)/(6x^3)^2

    (6x^3)^2 is the common denom!

    Please help
    -(18x^4) = -1 \times 6 \times 3 \times x^3 \times x

    24x^3 = 4 \times 6 \times x^2 \times x
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  3. #3
    A riddle wrapped in an enigma
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    Quote Originally Posted by wolfhound View Post
    Hello
    Can someone tell me how to simplify this further?

    (-18x^4)+(24x^3)/(6x^3)^2

    (6x^3)^2 is the common denom!

    Please help
    Hi wolfhound,

    Just to add a little to what e^{i\pi} said....

    \frac{-18x^4+24x^3}{(6x^3)^2}=\frac{-6x^3(3x-4)}{(6x^3)(6x^3)}

    Can you take it from there?
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  4. #4
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    Smile

    Thank you e^(i*pi).


    Quote Originally Posted by masters View Post
    Hi wolfhound,

    Just to add a little to what e^{i\pi} said....

    \frac{-18x^4+24x^3}{(6x^3)^2}=\frac{-6x^3(3x-4)}{(6x^3)(6x^3)}

    Can you take it from there?
    Yes this is the final answer I needed \frac{-18x^4+24x^3}{(6x^3)^2}=\frac{-6x^3(3x-4)}{(6x^3)(6x^3)}
    Thanks
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  5. #5
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by wolfhound View Post
    Thank you e^(i*pi).




    Yes this is the final answer I needed \frac{-18x^4+24x^3}{(6x^3)^2}=\frac{-6x^3(3x-4)}{(6x^3)(6x^3)}
    Thanks
    Surely 6x^3 cancels?
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