simplify..need help

**wolfhound** · January 22nd 2010, 11:57 AM

Hello
Can someone tell me how to simplify this further?

(-18x^4)+(24^3)/(6x^3)^2

(6x^3)^2 is the common denom!

Please help

**e^(i*pi)** · January 22nd 2010, 12:01 PM

Originally Posted by wolfhound

Hello
Can someone tell me how to simplify this further?

(-18x^4)+(24^3)/(6x^3)^2

(6x^3)^2 is the common denom!

Please help

$-(18x^4) = -1 \times 6 \times 3 \times x^3 \times x$

$24x^3 = 4 \times 6 \times x^2 \times x$

**masters** · January 22nd 2010, 12:17 PM

Originally Posted by wolfhound

Hello
Can someone tell me how to simplify this further?

(-18x^4)+(24x^3)/(6x^3)^2

(6x^3)^2 is the common denom!

Please help

Hi wolfhound,

Just to add a little to what $e^{i\pi}$ said....

$\frac{-18x^4+24x^3}{(6x^3)^2}=\frac{-6x^3(3x-4)}{(6x^3)(6x^3)}$

Can you take it from there?

**wolfhound** · January 22nd 2010, 12:59 PM

Thank you e^(i*pi).

Originally Posted by masters

Hi wolfhound,

Just to add a little to what $e^{i\pi}$ said....

$\frac{-18x^4+24x^3}{(6x^3)^2}=\frac{-6x^3(3x-4)}{(6x^3)(6x^3)}$

Can you take it from there?

Yes this is the final answer I needed $\frac{-18x^4+24x^3}{(6x^3)^2}=\frac{-6x^3(3x-4)}{(6x^3)(6x^3)}$
Thanks

**e^(i*pi)** · January 22nd 2010, 01:27 PM

Originally Posted by wolfhound

Thank you e^(i*pi).

Yes this is the final answer I needed $\frac{-18x^4+24x^3}{(6x^3)^2}=\frac{-6x^3(3x-4)}{(6x^3)(6x^3)}$
Thanks

Surely $6x^3$ cancels?

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