Im not quite sure how to find the domain on the function f(x)=the square root of x squared-4
Hi bastropgarl,
$\displaystyle f(x)=\sqrt{x^2-4}$
The domain is all values of x such that $\displaystyle x^2-4 \ge 0$
This graph has x-intercepts are -2 and +2.
The domain will be the values to the left of -2 and to the right of +2. The values between -2 and +2 are not part of the domain. For instance, zero is not in the domain.
Domain = $\displaystyle \{x|x \ge 2 \ \ or \ \ x \le -2\}$