how do you find the domain of the function f(x)=9-x over the square root of x+7
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Originally Posted by bastropgarl how do you find the domain of the function f(x)=9-x over the square root of x+7 Hi bastropgarl, The denominator cannot = 0. f(x ) would be undefined. x + 7 cannot be negative within the set of real numbers. You would have the square root of a negative number. So, x + 7 > 0 Therefore, the domain = {x | x > -7}.
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