how do you find the domain of the function f(x)=9-x over the square root of x+7
Hi bastropgarl,
$\displaystyle f(x)=\frac{9-x}{\sqrt{x+7}}$
The denominator cannot = 0. f(x ) would be undefined.
x + 7 cannot be negative within the set of real numbers. You would have the square root of a negative number.
So, x + 7 > 0
Therefore, the domain = {x | x > -7}.