how do you find the domain of the function f(x)=the square root of 3x-2
Follow Math Help Forum on Facebook and Google+
Originally Posted by bastropgarl how do you find the domain of the function f(x)=the square root of 3x-2 the domain of a function is the set of all input values (in this case, x-values) for which the functions is defined. is defined for all real numbers such that . what do you think the domain off your function is?
x is greater then or equal to -two over three
Originally Posted by bastropgarl x is greater then or equal to -two over three Not -2/3 as 2/3 is the right magnitude but consider the sign
sorry but im still not grasping this
Originally Posted by bastropgarl sorry but im still not grasping this as e^(i*pi) said, all you needed to do was change the sign... The domain is all real so that
Originally Posted by bastropgarl sorry but im still not grasping this The equation to solve is the one posted by Jhevon immediately above. When I did f(-0.5) that was to prove that is not correct by picking a value of x that is greater than -2/3. The negative result shows it's incorrect
View Tag Cloud