I read somewhere that you can get the coordinates for the peak of a quadratic equation by just rearranging the equation. I forgot how it was done though. Something like
is this correct? and how would you do for
? Thanks for any advice.
Thanks so much for the help!
I've been trying my hand at the second part of this question, but I can't seem to get to the answer shown in my book...
the second part is to get the minima of
and I thought the answer would reveal itself if I factorised and solved for , but the answer is apparently ... I was not even close... what exactly are you supposed to do to get to that answer?
I assume that you have calculated:
Therefore the vertex has the coordinates
With a parabola opening up the f(a)-value of the vertex determines the minimum. The vertex is the lowest point of all points of the graph of f. Therefore