1. ## Divide the expression

I want to make sure that my answer is correct: divide 27z +23z + 6z^3 / 2z^3 I have 3z+7?

2. $\frac{27z + 23z^2 + 6z^3}{2z^3} = \frac{27z}{2z^2} + \frac{23z^2}{2z^2}+ \frac{6z^3}{2z^3} = \frac{27}{2z} + \frac{23}{2} + 3 = \frac{27}{2z} + \frac{29}{2}= \frac{27+29z}{2z}$

3. Oops! I forgot an exponenet. The expression should read 27z + 23z^2 + 6z^3 divided by 2z +3=?

4. Oops! I forgot an exponent. The expression should be 27z + 23z^2 + 6z^3 divided by 2z + 3 = ?? Thanks

5. I edited my first post to reflect the change in the equation.