I want to make sure that my answer is correct: divide 27z +23z + 6z^3 / 2z^3 I have 3z+7?
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$\displaystyle \frac{27z + 23z^2 + 6z^3}{2z^3} = \frac{27z}{2z^2} + \frac{23z^2}{2z^2}+ \frac{6z^3}{2z^3} = \frac{27}{2z} + \frac{23}{2} + 3 = \frac{27}{2z} + \frac{29}{2}= \frac{27+29z}{2z}$
Last edited by statmajor; Jan 20th 2010 at 09:03 AM.
Oops! I forgot an exponenet. The expression should read 27z + 23z^2 + 6z^3 divided by 2z +3=?
Oops! I forgot an exponent. The expression should be 27z + 23z^2 + 6z^3 divided by 2z + 3 = ?? Thanks
I edited my first post to reflect the change in the equation.
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