$\displaystyle 2/x<x-1$

Since Im not allowed to multiply by x I canīt work it out.

Never done this kind of stuff before.

$\displaystyle 2/x<x-1$ -> $\displaystyle 2/x -x +1< 0$

I can wright it as (2-x^2+x)/x <0

Multiplying $\displaystyle (-1)$ gives me $\displaystyle (x^2-x-2)/x>0$

Whatever I do I canīt get it right....

All help apprecieted.