Never mind solved
Sure I did it this way ( if I understood it correctly.
/ add: -x+1
/make denominator same
/*(-1)
Now I solved for x with:
X1 = 2
X2 = (-1)
Now So I got the intervalls (-1);(0);(2)
So i picked a number in all intervalls + a number below (-1) and one above (2).
That gave me x>(-1)
or x>2
and not 0 cause that is undefined...