1. x^2 + 4x + 5 = 0

=> x = [-4 +/- sqrt(16 - 4(5))]/2 ......by the quadratic formula

=> x = [-4 +/- sqrt(-4)]/2

=> x = (-4 +/- 2i)/2

=> x = -2 + i or -2 - i

2. I will attach a figure soon. notice that if the first ship travels at 22 mph for 2.9 hrs, it will cover a distance of 63.8 miles. if the second ship travels at 28 mph for 2.9 hours, it will cover a distance of 81.2 miles. so we have a triange with two adjacent sides, one 63.8 miles in length, the other 81.2 miles in length and an angle of 130 degrees between them. we want to find the length of the side opposite to the 130 degree angle. we use the cosine rule (or the law of cosines as some call it).

by the cosine rule:

a^2 = b^2 + c^2 - 2bc*cos(A)

=> a^2 = (63.8)^2 + (81.2)^2 - 2(63.8)(81.2)cos(130)

=> a^2 = 10663.88 - 10361.12*cos(130)

=> a^2 = 10663.88 - 10361(-0.64279)

=> a^2 = 17323.904

=> a = sqrt(17323.904)

=> a = 131.62 miles

therefore the distance between the ships after 2.9 hrs is 131.62 miles