Thread: finding points on the curve

Hi, can someone explain to me how to solve the following question
Find the points on the curve y= 2/3x-2 where the tangent is parallel to the line y=-3/2 x-1
This what I did:
since m is given and b intercept:
y= -3/2x-1
2/3x-2=-3/2x-1
then i am stuck and dont know how to solve it.Help would be appreciated
Thanx

I'm not sure of your notation. I believe your first equation must be
y=2/(3x)-2, i.e., x is in the denominator. Do you know how to find the derivative of 2/(3x)-2? If so, that represents the slope of the first equation at any point, x. Use the slope of the second equation and what you know about parallel lines to finish.