If g(x) = x * 2^x, then g(a+1) - g(a)=

(a) (a+2)2^a

(b) (2a+1)2^a

(c) (2a-1)2^1

(d) (a+1)2^a+1

(e) (a)2^a+1

Results 1 to 4 of 4

- January 19th 2010, 03:32 AM #1

- Joined
- Sep 2008
- Posts
- 114

- January 19th 2010, 04:24 AM #2

- Joined
- Nov 2005
- From
- someplace
- Posts
- 14,972
- Thanks
- 4

- January 19th 2010, 04:52 AM #3

- Joined
- Sep 2008
- Posts
- 114

- January 19th 2010, 05:06 AM #4