If g(x) = x * 2^x, then g(a+1) - g(a)=

(a) (a+2)2^a

(b) (2a+1)2^a

(c) (2a-1)2^1

(d) (a+1)2^a+1

(e) (a)2^a+1

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- Jan 19th 2010, 03:32 AM #1

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- Jan 19th 2010, 04:24 AM #2

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- Jan 19th 2010, 04:52 AM #3

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- Jan 19th 2010, 05:06 AM #4