If g(x) = x * 2^x, then g(a+1) - g(a)=

(a) (a+2)2^a

(b) (2a+1)2^a

(c) (2a-1)2^1

(d) (a+1)2^a+1

(e) (a)2^a+1

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- Jan 19th 2010, 03:32 AMjuliakSAT Problem
If g(x) = x * 2^x, then g(a+1) - g(a)=

(a) (a+2)2^a

(b) (2a+1)2^a

(c) (2a-1)2^1

(d) (a+1)2^a+1

(e) (a)2^a+1 - Jan 19th 2010, 04:24 AMCaptainBlack
- Jan 19th 2010, 04:52 AMjuliak
Thank you very very much!

(sorry but) another question I have:

Which of the following CANNOT represent the degree measure of an equiangular polygon?

(a) 165

(b) 162

(c) 140

(d) 125

(e) 90 - Jan 19th 2010, 05:06 AMProve It
The internal sum of a polygon is given by $\displaystyle (n - 2)180^\circ$, where $\displaystyle n$ is the number of sides.

If it is a regular polygon then all the angles are equal. Since you have $\displaystyle n$ angles, then if $\displaystyle \theta$ is one of the angles

$\displaystyle n\theta = (n - 2)180^\circ$.

So $\displaystyle \theta = \frac{(n - 2)180^\circ}{n}$.

So now substitute some values for $\displaystyle n$ and see which ones that you have listed apply.