Can someone help me divide the following expression: 112a^0b^3c^-4/ 48a^3b^0c^3 ? Thanks much!
$\displaystyle \frac{112a^0b^3c^-4}{48a^3b^0c^3}$.
So, what we should do here is subtract all powers of like bases in the denominator from those that are in the numerator...
So....
$\displaystyle \frac{112a^0b^3c^{-4}}{48a^3b^0c^3}=\frac{112a^{0-3}b^{3-0}c^{-4-3}}{48}=\frac{112a^{-3}b^3c^{-7}}{48}$
So, note that the negative exponenets go into the denominator and become positive leaving us with
$\displaystyle \frac{112b^3}{48a^3c^7}$
Now, reduce the numerical coefficients
$\displaystyle \frac{7b^3}{3a^3c^7}$