Can someone help me divide the following expression: 112a^0b^3c^-4/ 48a^3b^0c^3 ? Thanks much!
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Originally Posted by jay1 Can someone help me divide the following : 112a^0b^3c^-4/ 48a^3b^0c^3 ? Thanks much!
Last edited by bigwave; January 18th 2010 at 09:46 PM. Reason: to show solved expression
I think that it may be: If this is correct, then remember that any value to the power of zero equals one, and
Originally Posted by jay1 Can someone help me divide the following expression: 112a^0b^3c^-4/ 48a^3b^0c^3 ? Thanks much! . So, what we should do here is subtract all powers of like bases in the denominator from those that are in the numerator... So.... So, note that the negative exponenets go into the denominator and become positive leaving us with Now, reduce the numerical coefficients
That makes sense now Von Nemo..Thanks! Now, could someone help me verify my answer on performing the indicated operations and simplfying: 5a+3/a^2 +13a +12 - 2a-3/a^2 + 13a + 12 I have: -3(a+2)/(a+12)(a+1) ?
You should really use some parentheses. Do you mean: ??
Originally Posted by Stroodle You should really use some parentheses. Do you mean: ?? I'm sorry.. It's (5a +3 /a^2 +13a +12) - (2a - 3/a^2 +13a +12) My answer was 3(a+2)/(a+12)(a+1) ?? Thanks!
If you mean to simplify then is correct.
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