Originally Posted by
crystal91 Hi, can someone check the below answer?
The height in meters of a ball dropped from the top of CN tower is given by h(t)= -4.9t^2+450
find the average velocity for the first two seconds?
h(0)=-4.9(0)^2+450
h(0)=450
h(2)= 430.4
AROC= 430.4-450/2-0
AROC= -9.8m/s