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Quote: Originally Posted by crystal91 Hi, can someone check the below answer? The height in meters of a ball dropped from the top of CN tower is given by h(t)= -4.9t^2+450 find the average velocity for the first two seconds? h(0)=-4.9(0)^2+450 h(0)=450 h(2)= 430.4 AROC= 430.4-450/2-0 AROC= -9.8m/s By definition, the answer is given by $\displaystyle \frac{h(2) - h(0)}{2 - 0}$ so assuming that your arithmetic is correct your answer will also be correct.