Hi i need help on where i have gone wrong in the following equations:
1)Solve for real values x and y.
x=1 or x=-3
2)Solve for real values x and y.
Also another question does and
P.S
For 2
a complex number z = 0 if and only if Re(z) = 0 and Im(z) =0
(x^2 - y^2) + i (2xy -18) = 0
x^2 = y^2 x = + y
and 2xy = 18
If x= y 2x^2 = 18 x= +3
If x = -y -2x^2 =18 and there are no solutions
only solutions are (3,3) and (-3,-3)
For 1)
(x+2i)(x-2i) = x^2 + 2ix - 2ix - 4i^2 = x^2 + 4
also
Even if
how do you conclude 4x+12 = 9 -x^2 ?
you should have x^2 + 4 = 5 -12 i
x^2 = 1-12i
if x is real x^2 must be real so there are no solutions
yes i^2 =-1 and -i^2 = 1