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Math Help - Basic math - currious if I am handling it correctly

  1. #1
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    Basic math - currious if I am handling it correctly

    little unsure on some exponent type math I did...

    when I did the volume I took (4/3)(pie)(r)^3 basically just plugged in (1.2X10^-15) into my figures and it kicked out something approaching:
    volume = - 2.44 X 10^7


    I then divided Mass/Volume:

    (1.67X10^-27)/(-2.44X10^7) = 6.84X10^-35


    am I using these exponents correctly in scientific notation and getting the approximate right answers?


    Thanks

    Brian
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by wilder7bc View Post
    little unsure on some exponent type math I did...

    when I did the volume I took (4/3)(pie)(r)^3 basically just plugged in (1.2X10^-15) into my figures and it kicked out something approaching:
    volume = - 2.44 X 10^7


    I then divided Mass/Volume:

    (1.67X10^-27)/(-2.44X10^7) = 6.84X10^-35


    am I using these exponents correctly in scientific notation and getting the approximate right answers?


    Thanks

    Brian
    Please, if you would be so kind...Cite the given problem.
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  3. #3
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    Quote Originally Posted by VonNemo19 View Post
    Please, if you would be so kind...Cite the given problem.

    Ok I had typed it up once but took it out so I didnt have to much information, I didnt want to clutter up someone else brain as my brain remains cluttered lol



    A proton which is the Nucleus of a hydrogen atom can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67X10^-27kg

    (a). Determine the density of the proton

    (b). state how your answer to part (a) compares with the density of Osmium, given in Table 14.1 (that was Osminum 22.6X10^3)

    My formulas

    Density = P = M/V Mass per unit volume

    Volume of sphere = (4/3)(pi)(r)^3

    my data:

    Proton
    Mass 1.67X10^-27kg
    Diameter 2.4fm = (if I did scientific notation correctly) 2.4X10^-15
    radius 1.2X10^-15


    Osminum
    Mass 22.6X10^3


    I then plugged things in


    (4/3)(pi)(1.2X10^-15)^3 = -2.44X10^7

    Then divided mass by volume


    (a). (1.67X10^-27)/(2.44X10^7) = 6.84X10^-35

    (b). Density of proton is way way way smaller than Osminum

    Ugggg.... this stuff is so hard to type which is why I asked a about a program in software part... maybe I should start trying to use word to do all this I just get slowed down a ton hunting for symbols!

    Thanks,

    Brian
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