# Thread: Value of x, over 1

1. ## Value of x, over 1

Sorry, didn't really know what title to use

How did I get this question wrong?
what is $\frac{1}{x+2}$ given that $\frac{1}{x}=3.5$???

My WIP
EDIT: sorry realised my fault. But can anyone answer me? I need the method because I know that answer is 7/16

2. Originally Posted by Mukilab
Sorry, didn't really know what title to use

How did I get this question wrong?
what is $\frac{1}{x+2}$ given that $\frac{1}{x}=3.5$???

My WIP
EDIT: sorry realised my fault. But can anyone answer me? I need the method because I know that answer is 7/16
Solving the equation

$\frac{1}{x}=3.5$

$x=\frac{1}{3.5}$

Which implies that $\frac{1}{x+2}=\frac{1}{\frac{1}{3.5}+2}$

3. Originally Posted by Mukilab
Sorry, didn't really know what title to use

How did I get this question wrong?
what is $\frac{1}{x+2}$ given that $\frac{1}{x}=3.5$???

My WIP
EDIT: sorry realised my fault. But can anyone answer me? I need the method because I know that answer is 7/16
if $\frac{1}{x} = 3.5$ , then $x = \frac{1}{3.5} = \frac{2}{7}$

$\frac{1}{x+2} = \frac{1}{\frac{2}{7} + 2} \cdot \frac{7}{7} =$ ?

4. Originally Posted by skeeter
if $\frac{1}{x} = 3.5$ , then $x = \frac{1}{3.5} = \frac{2}{7}$

$\frac{1}{x+2} = \frac{1}{\frac{2}{7} + 2} \cdot \frac{7}{7} =$ ?

= $\frac{7}{\frac{2}{7}\cdot \frac{14}{1}}=\frac{7}{28}=\frac{1}{4}?$

5. Originally Posted by Mukilab
= $\frac{7}{\frac{2}{7}\cdot \frac{14}{1}}=\frac{7}{28}=\frac{1}{4}?$

No.

$\frac{1}{\frac{2}{7}+2}\cdot\frac{7}{7}=\frac{7}{\ frac{2}{7}(7)+2(7)}=\frac{7}{2+14}=\frac{7}{16}$