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Math Help - Value of x, over 1

  1. #1
    Senior Member Mukilab's Avatar
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    Value of x, over 1

    Sorry, didn't really know what title to use

    How did I get this question wrong?
    what is \frac{1}{x+2} given that \frac{1}{x}=3.5???

    My WIP
    EDIT: sorry realised my fault. But can anyone answer me? I need the method because I know that answer is 7/16
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by Mukilab View Post
    Sorry, didn't really know what title to use

    How did I get this question wrong?
    what is \frac{1}{x+2} given that \frac{1}{x}=3.5???

    My WIP
    EDIT: sorry realised my fault. But can anyone answer me? I need the method because I know that answer is 7/16
    Solving the equation

    \frac{1}{x}=3.5


    x=\frac{1}{3.5}

    Which implies that \frac{1}{x+2}=\frac{1}{\frac{1}{3.5}+2}
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  3. #3
    MHF Contributor
    skeeter's Avatar
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    Quote Originally Posted by Mukilab View Post
    Sorry, didn't really know what title to use

    How did I get this question wrong?
    what is \frac{1}{x+2} given that \frac{1}{x}=3.5???

    My WIP
    EDIT: sorry realised my fault. But can anyone answer me? I need the method because I know that answer is 7/16
    if \frac{1}{x} = 3.5 , then x = \frac{1}{3.5} = \frac{2}{7}


    \frac{1}{x+2} = \frac{1}{\frac{2}{7} + 2} \cdot \frac{7}{7} = ?
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  4. #4
    Senior Member Mukilab's Avatar
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    Quote Originally Posted by skeeter View Post
    if \frac{1}{x} = 3.5 , then x = \frac{1}{3.5} = \frac{2}{7}


    \frac{1}{x+2} = \frac{1}{\frac{2}{7} + 2} \cdot \frac{7}{7} = ?

    = \frac{7}{\frac{2}{7}\cdot \frac{14}{1}}=\frac{7}{28}=\frac{1}{4}?
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  5. #5
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by Mukilab View Post
    = \frac{7}{\frac{2}{7}\cdot \frac{14}{1}}=\frac{7}{28}=\frac{1}{4}?

    No.

    \frac{1}{\frac{2}{7}+2}\cdot\frac{7}{7}=\frac{7}{\  frac{2}{7}(7)+2(7)}=\frac{7}{2+14}=\frac{7}{16}
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