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Thread: [SOLVED] Determine value of variables in a matrices

  1. #1
    Newbie majax79's Avatar
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    [SOLVED] Determine value of variables in a matrices

    Hello,

    I have what I think is a solution, but I'm not sure. I would certainly appreciate any help. Here is the problem:

    Determine the value of each variable.

    $\displaystyle \left( {\begin{array}{*{20}{c}}
    {x + 3} & {y + 4} \\
    7 & { - 1} \\
    \end{array}} \right) = \left( {\begin{array}{*{20}{c}}
    6 & 0 \\
    7 & k \\
    \end{array}} \right)$

    My answer is x=3, y=3. Is that correct?
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  2. #2
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    Quote Originally Posted by majax79 View Post
    Hello,

    I have what I think is a solution, but I'm not sure. I would certainly appreciate any help. Here is the problem:

    Determine the value of each variable.

    $\displaystyle \left( {\begin{array}{*{20}{c}}
    {x + 3} & {y + 4} \\
    7 & { - 1} \\
    \end{array}} \right) = \left( {\begin{array}{*{20}{c}}
    6 & 0 \\
    7 & k \\
    \end{array}} \right)$

    My answer is x=3, y=3. Is that correct?
    Look at the corresponding components.

    $\displaystyle x + 3 = 6$

    $\displaystyle y + 4 = 0$

    $\displaystyle 7 = 7$

    $\displaystyle -1 = k$.


    Solve for $\displaystyle x, y, k$.
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  3. #3
    Master Of Puppets
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    Just equate positions from one matrix to the other

    $\displaystyle x+3=6$

    $\displaystyle y+4=0$

    $\displaystyle k=-1$

    Spoiler:
    $\displaystyle x=3, y=-4, k=-1$
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  4. #4
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    I just tried to solve the sum ..Is the solution x=3 and y=-4 correct for the above sum "Prove it"??
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  5. #5
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    Yes. And it should be obvious that $\displaystyle k = -1$.
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