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Math Help - Question on Fraction with exponent (how it works)

  1. #1
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    Question on Fraction with exponent (how it works)

    I was going through my math made easy tapes for calculus as I review this(its been 13 years since calc I, and even longer for trig, and alg.)

    The professor sets up a formula

    g(x) =X^2 + (1)/(x)^2

    Now I am not worried about the calc problem I understand that its simple enough.

    What confused me is the rule for how he changed 1 divided by X squared to
    X raised to the negative 2 power.

    (1)/(x)^2 = (X)^-2 could someone break down the relationship as I do not remember this one..

    Also perhaps the name of what this is called so I can try to find it on google.

    Thanks,

    Brian
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Detroit, MI
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    Quote Originally Posted by wilder7bc View Post
    I was going through my math made easy tapes for calculus as I review this(its been 13 years since calc I, and even longer for trig, and alg.)

    The professor sets up a formula

    g(x) =X^2 + (1)/(x)^2

    Now I am not worried about the calc problem I understand that its simple enough.

    What confused me is the rule for how he changed 1 divided by X squared to
    X raised to the negative 2 power. This is from the laws of exponents several semesters ago. I suggest brushing up.

    (1)/(x)^2 = (X)^-2 could someone break down the relationship as I do not remember this one..

    Also perhaps the name of what this is called so I can try to find it on google.

    Thanks,

    Brian
    .
    Follow Math Help Forum on Facebook and Google+

  3. #3
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    Joined
    Jan 2010
    Posts
    15

    Thank you!

    That was exactly what I needed... With the name I was able to find a pdf with all the rules

    So many things I have forgotten anyway this was:

    #7: Negative Law of Exponents: If the base is powered by the
    negative exponent, then the base becomes reciprocal with the
    positive exponent.


    Now I can move forward again, After you get an idea of the boundaries you can then see the relationship between the roots and powers which allows me to prove the law =)

    as always this site is great I am going to have to make a donation I think as this is probably one of the best sites I have been on and people are always very helpful.

    Thanks again!
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