1. ## Simplifying rational expressions

Any help with these would be greatly appreciated thank you!

6.) (x^2 - 36) * [(3x + 1) / (x + 6)]

(y^2 - 9) / [(y + 3) / (y - 3)]

2. Originally Posted by iDrum
Any help with these would be greatly appreciated thank you!

6.) (x^2 - 36) * [(3x + 1) / (x + 6)]

(y^2 - 9) / [(y + 3) / (y - 3)]
You need to use the difference of 2 squares rule on both problems.

It is $a^2-b^2= (a-b)(a+b)$

Here's a kick start

$
x^2 - 36 = x^2 - 6^2 = (x-6)(x+6)
$

3. Originally Posted by iDrum
Any help with these would be greatly appreciated thank you!

6.) (x^2 - 36) * [(3x + 1) / (x + 6)]

(y^2 - 9) / [(y + 3) / (y - 3)]
rewrite
$\frac {y^2-9}{1}\ \frac{y-3}{y+3}$

then
$\frac {(y+3)(y-3)}{1}\ \frac{y-3}{y+3}$

see the rest?