Help!! I need help finding x.
2x – (7 + x) < x
2x - 7 - x <= x
x - 7 <= x
The x cancels out, so is the answer that circle with the diagonal line through it?
$\displaystyle 2x - (7 + x) \leq x$
$\displaystyle 2x - 7 - x \leq x$
$\displaystyle x - 7 \leq x$
$\displaystyle -7 \leq 0$
So this equality holds for any $\displaystyle x$, because $\displaystyle -7$ is indeed smaller than $\displaystyle 0$.
EDIT : erf Skeeter beat me to it
No, no !
Regardless of the value of $\displaystyle x$, the inequality holds, so I guess you could write this $\displaystyle x = \mathbb{R}$, or :
$\displaystyle \forall x \in \mathbb{R}$, $\displaystyle 2x - (7 + x) \leq x$
A less elegant but more direct way to write it could be : $\displaystyle x = (-\infty, +\infty)$, $\displaystyle x \in \mathbb{R}$.