1. ## Intermediate Algebra question

I have a test tomorrow in my Intermediate Algebra class and need this problem solved.

Randall wants to mix 50 lb of nuts worth $2 per lb with some nuts worth$6 per lb to make a mixture worth $5 per lb. How many pounds of$6 nuts must he use?

The answer is 150lb, but I don't know how to get to that.

2. Originally Posted by Justiceapple
I have a test tomorrow in my Intermediate Algebra class and need this problem solved.

Randall wants to mix 50 lb of nuts worth $2 per lb with some nuts worth$6 per lb to make a mixture worth $5 per lb. How many pounds of$6 nuts must he use?

The answer is 150lb, but I don't know how to get to that.
Let x be the pounds of $6 nuts needed, which would cost$6x.

The cost of the $2 nuts is$100.

The weight of the mixture will be 50 + x.

We want the cost per pound = (total cost)/(total weight) = 5

=> (100 + 6x)/(50 + x) = 5

Now solve for x

3. (100 + 6x)/(50 + x) = 5

My calculation doesn't say 150...
How does this become 150???
Thank you...

4. Originally Posted by Justiceapple
(100 + 6x)/(50 + x) = 5

My calculation doesn't say 150...
How does this become 150???
Thank you...
how did you try to solve this? post your work.

5. I tried to divide (100 + 6x) by (50 + x) = 5
so, 100 and 50 became 2, 6x/x became 6x, =5.

2+6x= 5....???

6. Originally Posted by Justiceapple
I tried to divide (100 + 6x) by (50 + x) = 5
so, 100 and 50 became 2, 6x/x became 6x, =5.

2+6x= 5....???
no no no. what rules told you you can do that? that is not mathematically sound. $\displaystyle \frac{a + b}{c + d} ~{\color{red} \ne}~ \frac ac + \frac bd$. make sure you do not do something like that on your test tomorrow (!)

begin by multiplying both sides by (50 + x). what happens?

(by the way, 6x/x = 6, not 6x)

7. ## wow!

WOWWWWW!!! I really said "Wooow!!" out loud when I solved it
Thank you!!!!! so much!

8. Originally Posted by Justiceapple
WOWWWWW!!! I really said "Wooow!!" out loud when I solved it
Thank you!!!!! so much!
ok, good job

keep studying