Find the zeros of the function h(x)= x^2 + 23x + 60 by factoring. __ I know I need to set the problem to h(x) = x^2 + 23x + 60 = 0 But I'm not quite sure what to factor out.
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Originally Posted by Caturdayz Find the zeros of the function h(x)= x^2 + 23x + 60 by factoring. __ I know I need to set the problem to h(x) = x^2 + 23x + 60 = 0 But I'm not quite sure what to factor out. you can factor it as (x + a)(x + b) where a and b are two numbers such that, when you multiply them you get 60 and when you add them you get 23
(x-20)(x-3) Would work, thanks.
Originally Posted by Caturdayz (x-20)(x-3) Would work, thanks. actually, no. if you add -20 and -3 you get -23 which is not the coefficient of the middle term
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