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Thread: Rational equations?

  1. January 14th 2010, 02:17 PM #1
    deekay930
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    Rational equations?

    Totally lost. ??

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  2. January 14th 2010, 02:26 PM #2
    rowe
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    I assume you want to simplify this expression?

    \frac{3(x-7)}{(x+2)(2x-1)} \cdot \frac{4x^2 + 6x -4}{4x-28}

    Start off by factorising your polynomial expressions on the right:

    \frac{3(x-7)}{(x+2)(2x-1)} \cdot \frac{2(x+2)(2x-1)}{4(x-7)}

    Multiply the two fractions:

    \frac{6(x-7)(x+2)(2x-1)}{4(x+2)(2x-1)(x-7)}

    Cancel out factors in denominator and numerator:

    \frac{6}{4} = \frac{3}{2}
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  3. January 14th 2010, 02:26 PM #3
    pickslides
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    Do some factoring on \frac{4x^2+6x-4}{4x-28}= \frac{2(x^2+3x-2)}{4(x-7)}

    Now have a go at factoring the quadratic in the numerator.
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  4. January 14th 2010, 02:32 PM #4
    rowe
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    Quote Originally Posted by pickslides View Post
    Do some factoring on \frac{4x^2+6x-4}{4x-28}= \frac{2(x^2+3x-2)}{4(x-7)}

    Now have a go at factoring the quadratic in the numerator.
    \frac{2(2x^2+3x-2)}{4(x-7)}?
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  5. January 14th 2010, 02:36 PM #5
    pickslides
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    Quote Originally Posted by rowe View Post
    \frac{2(2x^2+3x-2)}{4(x-7)}?
    Twas careless of me.
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  6. January 14th 2010, 02:43 PM #6
    rowe
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    Quote Originally Posted by pickslides View Post
    Twas careless of me.
    Sorry, I know you know- but since you highlighted a step my answer didn't, I didn't want our help seeker getting confused!
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