16x^2+6x^2+28x=0
How would you factorise this? ]CHeers
Hello HarisJudging from the title of your post, I suspect you might mean:
$\displaystyle 16x^3+6x^2+28x = 0$If so, take out a factor $\displaystyle 2x$:
$\displaystyle 2x(8x^2+3x+14)=0$That's all the factorising that's possible. And the only real solution to the equation is $\displaystyle x = 0$.
Grandad