# Math Help - removing parameter t to find the locus

1. ## removing parameter t to find the locus

Find an equation connecting x and y, by removing the parameter t from the following:
$x = \frac{ct - \frac{c}{t^3}}{2}$
$y=\frac{\frac{c}{t} - t^3c}{2}$

Thanks

2. Originally Posted by differentiate
Find an equation connecting x and y, by removing the parameter t from the following:
$x = \frac{ct - \frac{c}{t^3}}{2}$
$y=\frac{\frac{c}{t} - t^3c}{2}$

Thanks
1. Simplify:

$x = \frac{ct - \frac{c}{t^3}}{2}~\implies~x=\dfrac{c(t^4-1)}{2t^3}$

$y=\frac{\frac{c}{t} - t^3c}{2}~\implies~y=\dfrac{c(1-t^4)}{2t}$

2. Then calculate

$\dfrac yx = -t^2$

3. Now continue!