if you meant 3900 kilometer by '3900k'....

Quote:

Originally Posted by

**Infiniti** Long time reader, first time poster

"An airliner traveling from Toronto to Vancouver took 5hrs to cover the 3900k trip against a headwind. The return trip, traveling with a tailwind that was twice the speed of the headwind took 4hours and 20 mins.

Hint: You will need to use the formula, distance = speed x time.

a) How fast were the headwind and the tailwind on the two trips

b) How fast would the airliner have flown in still air?)

Let the speed of the airplane as 'x km/hr'

Let the speed of the headwind as 'y km/hr'

Then the speed of the tailwind would be '2y km/hr'

Then you can get two simultaneous equations since 'distance = speed x time'

5(x-y)=3900

5(x+2y)=4500

If you solve the equation, it'll be clear that

the speed of the airplane is 3600 km/hr

the speed of the headwind is 60 km/hr

and the speed of the tailwind is 120 km/hr.

So the answer for the problem (a) would be 60km/hr and 120km/hr

And the answer for the problem (b) would be 3600km/hr