Math Help - Algebra Help!

1. Algebra Help!

Hello,

5000 = 100*2^(t/3)

thanks

2. do you know/remember how to do logarithms? (logs)

3. Originally Posted by artvandalay11
do you know/remember how to do logarithms? (logs)
I had a feeling that's where its going to end up at, I get to about here then i'm stuck...

4900 = 2^(t/3)

what's the next step?

4. you subtracted 100, but you have to divide by it

after that, take the log of both sides... then you can use a log rule to "Bring down" the exponenet.... do you know how to do this

5. Originally Posted by artvandalay11
you subtracted 100, but you have to divide by it

after that, take the log of both sides... then you can use a log rule to "Bring down" the exponenet.... do you know how to do this
oops, sorry for that silly mistake thanks..

500=2^(t/3)

i have no idea how to do the next step =/

6. Originally Posted by l flipboi l
oops, sorry for that silly mistake thanks..

500=2^(t/3)

i have no idea how to do the next step =/
That 500 should be a 50 as pickslides notes. 5000 divided by 100 is 50 not 500

We will take the log of both sides. There are special log rules that you need to remember. Logs were "invented" for dealing with these exact kinds of problems

$\log 50=\log 2^{\frac{t}{3}}$

$\log 50=\frac{t}{3} \log 2$

One of those important log rules is that you can bring down the exponent

now can you solve?

7. Originally Posted by artvandalay11

$\log 500=\log 2^{\frac{t}{3}}$

$\log 500=\frac{t}{3} \log 2$
You mean

$\log 50=\log 2^{\frac{t}{3}}$

$\log 50=\frac{t}{3} \log 2$

8. yes I do, sorry I just quoted and assumed the quote was correct, 5000 divided by 100 is 50 not 500

9. Originally Posted by artvandalay11
yes I do, sorry I just quoted and assumed the quote was correct, 5000 divided by 100 is 50 not 500

hahah geez =/ sorry

10. Originally Posted by pickslides
You mean

$\log 50=\log 2^{\frac{t}{3}}$

$\log 50=\frac{t}{3} \log 2$

how would you isolate the t from there.

11. Originally Posted by l flipboi l

how would you isolate the t from there.
using some very basic algebra

$\log 50=\frac{t}{3} \log 2$

$\frac{\log 50}{\log 2}=\frac{t}{3}$

$3\frac{\log 50}{\log 2}=t$

$t= 3\frac{\log 50}{\log 2}$

The rest is a job for Mr Calculator..