Originally Posted by

**jay1** I would like to verify that the answers that I have come up with are correct on the following 3 equations. I greatly appreciate it! (the numbers in red are exponents) 1) solve the equation 1/4a2 + 3/4 a=1 My answer is a=4 and a=1 ??? 2) Simplify the expression 2ab4 - 3 a2b2 - ab4 + a2b2 I have ab4 - 2a2b2 ??? and 3) Simplify the expression -2(4y2+3z3+5) + 3(2y2-5z3+3) My answer is -21z3 - 2y2 -1??? I thank you for the help!

If problem 1 is what I interpreted it to be, which is this:

$\displaystyle

\frac{1}{4a^2} + \frac{3}{4}a = 1

$

then

$\displaystyle

a=1, a=\frac{1+\sqrt{13}}{6}, \text{ and } a=\frac{1-\sqrt{13}}{6}

$.

However, if problem 1 is this:

$\displaystyle

\frac{1}{4a^2} + \frac{3}{4a} = 1

$

then

$\displaystyle

a=1, a= -\frac{1}{4}

$.

And if problem 1 is this:

$\displaystyle

\frac{1}{4}a^2 + \frac{3}{4}a = 1

$

then

$\displaystyle

a=1, a= -4

$.