Show that if logb(a)=c and logy(b)=c, then loga(y)=c^-2
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Hello KingV15 Originally Posted by KingV15 Show that if logb(a)=c and logy(b)=c, then loga(y)=c^-2 I generally reckon that the easiest way to solve log problems is to get rid of the logs as soon as possible! So let's try that here. ...(1) ...(2) and we need to show that: in other words that: Now from (1): ...(3) And from (2): from (3) Grandad
Hello, KingV15! Good job, Grandad! You used my favorite approach. Here's another . . . Show that if: . . . then: . Base-change Formula: . Multiply [3] by [4]: . . . Therefore: .
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