5*80 = 400 points to go around among the 4 students.
3 students received 100.
2 students stunk up the place and scored 50.
3(100) + 2(50) = 400 = mean*#ofStudents
In a certain game, each of the 5 players received a score between 0 and 100 inclusive. If their average(arithmetic mean) score was 80, what is the greatest possible number of the 5 players who dould have received a score of 50?
- None
- One
- Two
- Three
- Four
i know c but how?
whats the most efficient method to solve this type of the so called , your so "mean" killer question
5 pax with average score of 80. 5 x 80 = 400 marks in total.
How many could get 50?
5 could not as this would give only 250 marks
4 could not as 4 x 50 = 200 and last mark max could be 100 which leaves up 100 short
3 could not as 3 x 50 = 150 and even if both got 100, leaves us 50 marks short
2 works as 2 x 50 = 100 and 3 x 100 = 300 which gives us the correct marks.
therefore the max possible would be 2 pax