Results 1 to 6 of 6

Math Help - Solving

  1. #1
    Junior Member
    Joined
    Jan 2010
    Posts
    60

    Solving

    Just wondering if i am losing it, for the life of me i can't figure this out

    Please help, am i supposed to eliminate the denominator? am i supposed to cross multiply?

    2x+1/3x+2 = 4x-1/6x-5
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Banned
    Joined
    Oct 2009
    Posts
    769

    Next step

    Multiply both sides by 6x.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,236
    Thanks
    28
    G'day nuckers,

    You have to be careful how such a question is asked,

    Is the question

    \frac{2x+1}{3x+2} = \frac{4x-1}{6x-5}

    or

    2x+\frac{1}{3x}+2 =4x- \frac{1}{6x} -5

    brackets will make a big difference!

    I'm guessing it's \frac{2x+1}{3x+2} = \frac{4x-1}{6x-5}

    and therefore

    (2x+1)(6x-5) = (4x-1)(3x+2)

    Now expand each side and solve the quadratic.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    A riddle wrapped in an enigma
    masters's Avatar
    Joined
    Jan 2008
    From
    Big Stone Gap, Virginia
    Posts
    2,551
    Thanks
    12
    Awards
    1
    Quote Originally Posted by nuckers View Post
    Just wondering if i am losing it, for the life of me i can't figure this out

    Please help, am i supposed to eliminate the denominator? am i supposed to cross multiply?

    2x+1/3x+2 = 4x-1/6x-5
    EDIT: Just a wee bit late, but what the hey!
    Hi nuckers,

    I'm guessing that what you intended to state is this:

    \frac{2x+1}{3x+2}=\frac{4x-1}{6x-5}

    If that be the case, what you call "cross multiply" would work just fine.

    Remember to use parentheses to separate numerators and denominators. What you actually have written is:

    2x+\frac{1}{3x}+2=4x-\frac{1}{6x}-5 in which case wonderboy1953's suggestion should be followed.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Member
    Joined
    Mar 2008
    Posts
    182
    ...
    Last edited by Unenlightened; January 13th 2010 at 06:44 AM. Reason: Only first post showed up, and not the answers... how odd :-/
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor

    Joined
    Apr 2005
    Posts
    15,707
    Thanks
    1470
    Please notice that it is not, and should not be, a matter of what you are "supposed" to do! You can, if you like, 'eliminate the denominators' just because fractions are difficult to work with! And a good way of doing that is to "cross multiply". You are still at the level of "following rules" rather than "thinking". Try to get to the level of thinking out a problem rather than just following rules- because there are always problems where the rules don't apply!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. solving for x
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: November 7th 2009, 04:13 PM
  2. help solving for y
    Posted in the Algebra Forum
    Replies: 2
    Last Post: November 1st 2009, 10:25 AM
  3. help me in solving this
    Posted in the Discrete Math Forum
    Replies: 1
    Last Post: December 13th 2008, 01:51 PM
  4. Solving x'Px = v
    Posted in the Advanced Algebra Forum
    Replies: 0
    Last Post: December 11th 2008, 03:21 PM
  5. Replies: 3
    Last Post: October 11th 2006, 09:15 PM

Search Tags


/mathhelpforum @mathhelpforum