# class help please!

• Jan 12th 2010, 11:51 AM
daniking
I've been needing some help with my algebra class.. thank you!

The ordered pair (2, 16) is a solution for which equation(s)? Check all that apply.
A. y = 2x2
B. y = (2x)2
C. y = 2x + 2
D. y = (x + 2)2

Here is my final problem I'm stuck at.. I read through my book several times but it does not mention what I do... My teacher said we whent over it in class.. But being absent has it's downs. =/
• Jan 12th 2010, 12:55 PM
pickslides
Quote:

Originally Posted by daniking

The ordered pair (2, 16) is a solution for which equation(s)? Check all that apply.
A. y = 2x2
B. y = (2x)2
C. y = 2x + 2
D. y = (x + 2)2

For each equation substitute in $x=2$, if the result gives 16 then it is a solution, i'll do the first one

$y=2x^2$

$x=2$

$y=2(2)^2= 2\times 4 = 8 \neq 16$
• Jan 12th 2010, 01:55 PM
daniking
Quote:

Originally Posted by pickslides
For each equation substitute in $x=2$, if the result gives 16 then it is a solution, i'll do the first one

$y=2x^2$

$x=2$

$y=2(2)^2= 2\times 4 = 8 \neq 16$

Ummmm Yeah that answer you gave me was wrong lol. (Giggle)

But it still helped me out so ty (:
• Jan 12th 2010, 06:00 PM
mr fantastic
Quote:

Originally Posted by daniking
Ummmm Yeah that answer you gave me was wrong lol. (Giggle)

But it still helped me out so ty (:

pickslides knows that this option is wrong. In fact, he clearly indicated that it was wrong. He started with option A and showed it was wrong as an example of how to follow his good advice:
Quote:

Originally Posted by pickslides
For each equation substitute in http://www.mathhelpforum.com/math-he...7a4b424e-1.gif, if the result gives 16 then it is a solution

The expectation was that you would test the remaining options in the same way until you found the option that worked.

Please try to focus on understanding the help you are given instead of trying to score a cheap point.