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Thread: Negative powers and study habits

  1. January 12th 2010, 12:48 PM #16
    Jhevon
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Mukilab View Post
    Do you recommend any maths GCSE book I should study from? I got the CGP workbook...
    i do not have any recommendations. and the CGP workbooks, those come by topics, right? which one(s) do you have?

    you might find the following links useful. some have books listed, you can find reviews of them to decide if you think they'll be a good fit. others are just helpful sites or advice.

    EasyMaths - Free GCSE Maths tutorials, Sample Maths Exam papers, Books, Puzzles, Magic all helping to make learning maths easy!

    What are the best GCSE Revision Sites/Books? - Yahoo! UK & Ireland Answers

    GCSE Maths Books

    maybe e^(i*pi) will have some recommendations...
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  2. January 13th 2010, 08:17 AM #17
    Mukilab
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    Quote Originally Posted by Jhevon View Post
    i do not have any recommendations. and the CGP workbooks, those come by topics, right? which one(s) do you have?

    you might find the following links useful. some have books listed, you can find reviews of them to decide if you think they'll be a good fit. others are just helpful sites or advice.

    EasyMaths - Free GCSE Maths tutorials, Sample Maths Exam papers, Books, Puzzles, Magic all helping to make learning maths easy!

    What are the best GCSE Revision Sites/Books? - Yahoo! UK & Ireland Answers

    GCSE Maths Books

    maybe e^(i*pi) will have some recommendations...
    THanks
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  3. January 13th 2010, 02:55 PM #18
    Archie Meade
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    Hi Mukilab,

    here's something to practice with....

    3x=x+x+x

    x^3=x(x)x

    The exponent tells us how many x's are multiplied together.

    x^2x^3=[x(x)][x(x)x]=x^5=x^{2+3}

    \frac{x^5}{x^3}=\frac{x(x)x(x)x}{x(x)x}=x(x)=x^2=x ^{5-3}

    Also...

    \frac{x^5}{x^3}\ may\ be\ written\ x^5x^{-3}

    (x^2)^3=[x(x)][x(x)][x(x)]=x^6=x^{2(3)}

    (2^{-2})^{-2}=(\frac{1}{2^2})^{-2}=\frac{1}{(\frac{1}{2^2})^2}

    =\frac{1}{(\frac{1}{4^2})}=\frac{1}{(\frac{1}{16}) }

    =\frac{(16)(\frac{1}{16})}{\frac{1}{16}}=16\frac{( \frac{1}{16})}{(\frac{1}{16})}=16=2^4

    (2^{-2})^{-2}=2^{(-2)(-2)}=2^4
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