I cannot solve these 3 examples. If you know it, please help me.
To simplify calculations,
for (1), begin by factorising 35 to write it as a multiple of the single-digit terms, 5 and 7, may be simpler ways though.
For (2), 9 is a power of 3, 4 is a power of 2 and 6 is a multiple of 3 and 2.
For (3), 4 and 8 are powers of 2, 12 is a multiple of 2, but this is a quadratic in disguise.
Hello, x-mather!
These are truly ugly problems . . .
We have: .
. . . . . . . . .
. . . . . . . . . .
Multiply by 2: .
. . . .
Factor: .
. . . . . . . . .
Divide by 3: . .
. . . . . . . . . . . .
Divide by 2: . . . .
. . . . . . . . . . .
Take logs: . .
. . . . . . . . .
. . Therefore: . . . .