I cannot solve these 3 examples. If you know it, please help me.

http://content.imagesocket.com/images/_jj95c.JPG

Printable View

- January 12th 2010, 05:42 AMx-mather3 examples
I cannot solve these 3 examples. If you know it, please help me.

http://content.imagesocket.com/images/_jj95c.JPG - January 12th 2010, 06:00 AMArchie Meade
To simplify calculations,

for (1), begin by factorising 35 to write it as a multiple of the single-digit terms, 5 and 7, may be simpler ways though.

For (2), 9 is a power of 3, 4 is a power of 2 and 6 is a multiple of 3 and 2.

For (3), 4 and 8 are powers of 2, 12 is a multiple of 2, but this is a quadratic in disguise. - January 12th 2010, 06:05 AMx-mather
I understand what you said but what to do after it?

- January 12th 2010, 06:51 AMArchie Meade
Well, for (1)

simplest is to write

If x=0, then

However, I doubt that this is the way you are expected to solve,

since this answer is by inspection,

it is not a derived solution. - January 12th 2010, 07:01 AMArchie Meade

These are equal if x=0 - January 12th 2010, 07:16 AMOloria
The third is really simple.

Don't forget to find a domain of the function.

and a>0

- January 12th 2010, 07:30 AMArchie Meade
For Q2

continue - January 12th 2010, 07:32 AMOloria
2. Mulitply two sides of the equation throughout 6.

After simple transformation:

If I didn't make a mistake to give a result you need to use a logarithm. - January 12th 2010, 07:34 AMSoroban
Hello, x-mather!

These are trulyproblems . . .*ugly*

Quote:

We have: .

. . . . . . . . .

. . . . . . . . . .

Multiply by 2: .

. . . .

Factor: .

. . . . . . . . .

Divide by 3: . .

. . . . . . . . . . . .

Divide by 2: . . . .

. . . . . . . . . . .

Take logs: . .

. . . . . . . . .

. . Therefore: . . . .

- January 12th 2010, 07:34 AMOloria
Late, while I was writing I didn't see a new post appeared.