# Thread: Need Help With Fractions Questons

1. ## Need Help With Fractions Questons

1. Each car on a commuter train holds 20 people. On a particular morning, 5 cars were 90% full and 3 cars were 65% full. If the people were rearrenged to fill as many cars as possible, how many cars would be filled?

2. Use each of the digits 1,2,4,5,8, and 9 once to creat the greatest possible value of the following expression. The mixed numbers have to be in proper form, without being renamed.
( ) ( )/3 - ( ) ( )/6 + 7 ( )/( )

2. Originally Posted by puppy_wish

1. Each car on a commuter train holds 20 people. On a particular morning, 5 cars were 90% full and 3 cars were 65% full. If the people were rearrenged to fill as many cars as possible, how many cars would be filled?

2. Use each of the digits 1,2,4,5,8, and 9 once to creat the greatest possible value of the following expression. The mixed numbers have to be in proper form, without being renamed.
( ) ( )/3 - ( ) ( )/6 + 7 ( )/( )
1. Remember, "percentage" is a fancy word for saying "/100", (i've been saying that a lot lately). so 90% means 90/100 and 65% means 65/100 and so on. also, "of" in math means multiply. so when they say a car of the train is 90% full, it means there are 90% of 20 people in the car, which means there are 90/100 * 20 people in the car. ok, now to do the question.

90% of 20 is 0.9*20 = 18. so we have 5 cars with 18 people
65% of 20 is 0.65*20 = 13, so we have 3 cars with 13 people

so we have 5*18 + 3*13 = 129 people in all.
it takes 20 people to fill one car, so the amount of cars we can fill will be 129/20 cars = 6.45 cars. since we are only concerned with how many cars we can fill, the answer is 6. 6 cars will be filled with 20 people each if the people were rearranged.

2. Use each of the digits 1,2,4,5,8, and 9 once to creat the greatest possible value of the following expression. The mixed numbers have to be in proper form, without being renamed.
( 9) ( 2)/3 - ( 1) ( 5)/6 + 7 ( 4)/(5 )

3. Ok well i can help you with the first problem for sure. We know each car can hold 20 people. And 5 cars were 90% full, so the number of cars (5) * percentage of the full car 90% (.90) we get 90. So in 5 cars there were 90 people then the second part number of cars (3) * percentage of the full cars 65% (.65) = 39. So now we know that in total on all 8 cars there are 90+39 = 129 people on the cars. The final step would be to do 129/20 = 6.45 which is how many cars you would need if the people were rearranged to fill as many possible cars so 6 cars are completely full and the 7th is about half full. So the answer would be 7 because you still have people left over after the 6th car was full.

I'll try to figure out your second problem for you while I'm waiting to get help with my own homework I'm having trouble with lol.

Well nvm i guess someone beat me to it while i was posting to you.

4. I saw the message before but forgot to say thank you (silly me). Thank you tones!

5. Originally Posted by puppy_wish
I saw the message before but forgot to say thank you (silly me). Thank you tones!
All's well that ends well!

You're welcome