factoring expressions

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January 11th 2010, 09:23 PM
jay1

factoring expressions

Please assist me in completely factoring the following expressions: (the numbers are exponents) 1)16t3 - 50t2 + 36t I have 2t (8t+9)(T+2) is this correct???
2) 48u4v4 - 18u2v2 - 3u8v5 I'm stuck on this one
3) 4q2 + 27r ? Thank you!
January 11th 2010, 09:41 PM
bigwave

Quote:

Originally Posted by jay1

Please assist me in completely factoring the following expressions: (the numbers are exponents) 1)16t3 - 50t2 + 36t I have 2t (8t+9)(T+2) is this correct???
2) 48u4v4 - 18u2v2 - 3u8v5 I'm stuck on this one
3) 4q2 + 27r ? Thank you!

2)
$48u^4v^4-18u^2v^2-3u^8v^5$

$3u^2v^2(16u^2v^2-6-u^6v^3)$

are you sure these exponents are correct?
January 12th 2010, 09:06 AM
jay1

factoring expressions

Yes, Big Wave thank you!
Can you assist me with questions 1 and 3? I would appreciate it greatly.
January 12th 2010, 09:27 AM
masters

Quote:

Originally Posted by jay1

Please assist me in completely factoring the following expressions: (the numbers are exponents)

1) $16t^3 - 50t^2 + 36t$

I have $2t (8t+9)(t+2)$ is this correct???
Thank you!

Hi jay1,

Almost. You missed the sign.

$16t^3-50t^2+36t=2t(8t-9)(t-2)$
January 12th 2010, 09:34 AM
masters

Quote:

Originally Posted by jay1

Please assist me in completely factoring the following expressions: (the numbers are exponents)

3) $4q^2 + 27r$ ? Thank you!

jay1,

It would appear that this one is already in its simplest form. Make sure you copied it correctly.
January 12th 2010, 10:28 AM
jay1

Thanks I copied it incorrectly. It should read 4q2 + 27r4. Thanks for your help. Also to factor 2a3 - 128, is this prime?
January 12th 2010, 10:38 AM
masters

Quote:

Originally Posted by jay1

Thanks I copied it incorrectly. It should read 4q2 + 27r4. Thanks for your help. Also to factor 2a3 - 128, is this prime?

Hi jay1,

You still can't do anything with $4q^2+27r^4$

And for $2a^3-128$ , first factor out a 2.

$2(a^3-64)$ and recognize that $a^3-64$ is the difference of two cubes. You should know how to handle that one, don't you?

$2(a^3-4^3)=$
January 13th 2010, 11:12 AM
jay1

Masters, 2 (a-4)3 ??? (the 3 being an exponent)

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